Integrand size = 42, antiderivative size = 294 \[ \int \frac {(g \cos (e+f x))^{3/2} (c-c \sin (e+f x))^{7/2}}{(a+a \sin (e+f x))^{3/2}} \, dx=-\frac {22 c^4 (g \cos (e+f x))^{5/2}}{a f g \sqrt {a+a \sin (e+f x)} \sqrt {c-c \sin (e+f x)}}-\frac {66 c^4 g \sqrt {\cos (e+f x)} \sqrt {g \cos (e+f x)} E\left (\left .\frac {1}{2} (e+f x)\right |2\right )}{a f \sqrt {a+a \sin (e+f x)} \sqrt {c-c \sin (e+f x)}}-\frac {66 c^3 (g \cos (e+f x))^{5/2} \sqrt {c-c \sin (e+f x)}}{7 a f g \sqrt {a+a \sin (e+f x)}}-\frac {30 c^2 (g \cos (e+f x))^{5/2} (c-c \sin (e+f x))^{3/2}}{7 a f g \sqrt {a+a \sin (e+f x)}}-\frac {4 c (g \cos (e+f x))^{5/2} (c-c \sin (e+f x))^{5/2}}{f g (a+a \sin (e+f x))^{3/2}} \]
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Time = 1.00 (sec) , antiderivative size = 294, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.119, Rules used = {2929, 2930, 2921, 2721, 2719} \[ \int \frac {(g \cos (e+f x))^{3/2} (c-c \sin (e+f x))^{7/2}}{(a+a \sin (e+f x))^{3/2}} \, dx=-\frac {22 c^4 (g \cos (e+f x))^{5/2}}{a f g \sqrt {a \sin (e+f x)+a} \sqrt {c-c \sin (e+f x)}}-\frac {66 c^4 g \sqrt {\cos (e+f x)} E\left (\left .\frac {1}{2} (e+f x)\right |2\right ) \sqrt {g \cos (e+f x)}}{a f \sqrt {a \sin (e+f x)+a} \sqrt {c-c \sin (e+f x)}}-\frac {66 c^3 \sqrt {c-c \sin (e+f x)} (g \cos (e+f x))^{5/2}}{7 a f g \sqrt {a \sin (e+f x)+a}}-\frac {30 c^2 (c-c \sin (e+f x))^{3/2} (g \cos (e+f x))^{5/2}}{7 a f g \sqrt {a \sin (e+f x)+a}}-\frac {4 c (c-c \sin (e+f x))^{5/2} (g \cos (e+f x))^{5/2}}{f g (a \sin (e+f x)+a)^{3/2}} \]
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Rule 2719
Rule 2721
Rule 2921
Rule 2929
Rule 2930
Rubi steps \begin{align*} \text {integral}& = -\frac {4 c (g \cos (e+f x))^{5/2} (c-c \sin (e+f x))^{5/2}}{f g (a+a \sin (e+f x))^{3/2}}-\frac {(15 c) \int \frac {(g \cos (e+f x))^{3/2} (c-c \sin (e+f x))^{5/2}}{\sqrt {a+a \sin (e+f x)}} \, dx}{a} \\ & = -\frac {30 c^2 (g \cos (e+f x))^{5/2} (c-c \sin (e+f x))^{3/2}}{7 a f g \sqrt {a+a \sin (e+f x)}}-\frac {4 c (g \cos (e+f x))^{5/2} (c-c \sin (e+f x))^{5/2}}{f g (a+a \sin (e+f x))^{3/2}}-\frac {\left (165 c^2\right ) \int \frac {(g \cos (e+f x))^{3/2} (c-c \sin (e+f x))^{3/2}}{\sqrt {a+a \sin (e+f x)}} \, dx}{7 a} \\ & = -\frac {66 c^3 (g \cos (e+f x))^{5/2} \sqrt {c-c \sin (e+f x)}}{7 a f g \sqrt {a+a \sin (e+f x)}}-\frac {30 c^2 (g \cos (e+f x))^{5/2} (c-c \sin (e+f x))^{3/2}}{7 a f g \sqrt {a+a \sin (e+f x)}}-\frac {4 c (g \cos (e+f x))^{5/2} (c-c \sin (e+f x))^{5/2}}{f g (a+a \sin (e+f x))^{3/2}}-\frac {\left (33 c^3\right ) \int \frac {(g \cos (e+f x))^{3/2} \sqrt {c-c \sin (e+f x)}}{\sqrt {a+a \sin (e+f x)}} \, dx}{a} \\ & = -\frac {22 c^4 (g \cos (e+f x))^{5/2}}{a f g \sqrt {a+a \sin (e+f x)} \sqrt {c-c \sin (e+f x)}}-\frac {66 c^3 (g \cos (e+f x))^{5/2} \sqrt {c-c \sin (e+f x)}}{7 a f g \sqrt {a+a \sin (e+f x)}}-\frac {30 c^2 (g \cos (e+f x))^{5/2} (c-c \sin (e+f x))^{3/2}}{7 a f g \sqrt {a+a \sin (e+f x)}}-\frac {4 c (g \cos (e+f x))^{5/2} (c-c \sin (e+f x))^{5/2}}{f g (a+a \sin (e+f x))^{3/2}}-\frac {\left (33 c^4\right ) \int \frac {(g \cos (e+f x))^{3/2}}{\sqrt {a+a \sin (e+f x)} \sqrt {c-c \sin (e+f x)}} \, dx}{a} \\ & = -\frac {22 c^4 (g \cos (e+f x))^{5/2}}{a f g \sqrt {a+a \sin (e+f x)} \sqrt {c-c \sin (e+f x)}}-\frac {66 c^3 (g \cos (e+f x))^{5/2} \sqrt {c-c \sin (e+f x)}}{7 a f g \sqrt {a+a \sin (e+f x)}}-\frac {30 c^2 (g \cos (e+f x))^{5/2} (c-c \sin (e+f x))^{3/2}}{7 a f g \sqrt {a+a \sin (e+f x)}}-\frac {4 c (g \cos (e+f x))^{5/2} (c-c \sin (e+f x))^{5/2}}{f g (a+a \sin (e+f x))^{3/2}}-\frac {\left (33 c^4 g \cos (e+f x)\right ) \int \sqrt {g \cos (e+f x)} \, dx}{a \sqrt {a+a \sin (e+f x)} \sqrt {c-c \sin (e+f x)}} \\ & = -\frac {22 c^4 (g \cos (e+f x))^{5/2}}{a f g \sqrt {a+a \sin (e+f x)} \sqrt {c-c \sin (e+f x)}}-\frac {66 c^3 (g \cos (e+f x))^{5/2} \sqrt {c-c \sin (e+f x)}}{7 a f g \sqrt {a+a \sin (e+f x)}}-\frac {30 c^2 (g \cos (e+f x))^{5/2} (c-c \sin (e+f x))^{3/2}}{7 a f g \sqrt {a+a \sin (e+f x)}}-\frac {4 c (g \cos (e+f x))^{5/2} (c-c \sin (e+f x))^{5/2}}{f g (a+a \sin (e+f x))^{3/2}}-\frac {\left (33 c^4 g \sqrt {\cos (e+f x)} \sqrt {g \cos (e+f x)}\right ) \int \sqrt {\cos (e+f x)} \, dx}{a \sqrt {a+a \sin (e+f x)} \sqrt {c-c \sin (e+f x)}} \\ & = -\frac {22 c^4 (g \cos (e+f x))^{5/2}}{a f g \sqrt {a+a \sin (e+f x)} \sqrt {c-c \sin (e+f x)}}-\frac {66 c^4 g \sqrt {\cos (e+f x)} \sqrt {g \cos (e+f x)} E\left (\left .\frac {1}{2} (e+f x)\right |2\right )}{a f \sqrt {a+a \sin (e+f x)} \sqrt {c-c \sin (e+f x)}}-\frac {66 c^3 (g \cos (e+f x))^{5/2} \sqrt {c-c \sin (e+f x)}}{7 a f g \sqrt {a+a \sin (e+f x)}}-\frac {30 c^2 (g \cos (e+f x))^{5/2} (c-c \sin (e+f x))^{3/2}}{7 a f g \sqrt {a+a \sin (e+f x)}}-\frac {4 c (g \cos (e+f x))^{5/2} (c-c \sin (e+f x))^{5/2}}{f g (a+a \sin (e+f x))^{3/2}} \\ \end{align*}
Time = 14.51 (sec) , antiderivative size = 282, normalized size of antiderivative = 0.96 \[ \int \frac {(g \cos (e+f x))^{3/2} (c-c \sin (e+f x))^{7/2}}{(a+a \sin (e+f x))^{3/2}} \, dx=-\frac {66 (g \cos (e+f x))^{3/2} E\left (\left .\frac {1}{2} (e+f x)\right |2\right ) \left (\cos \left (\frac {1}{2} (e+f x)\right )+\sin \left (\frac {1}{2} (e+f x)\right )\right )^3 (c-c \sin (e+f x))^{7/2}}{f \cos ^{\frac {3}{2}}(e+f x) \left (\cos \left (\frac {1}{2} (e+f x)\right )-\sin \left (\frac {1}{2} (e+f x)\right )\right )^7 (a (1+\sin (e+f x)))^{3/2}}+\frac {(g \cos (e+f x))^{3/2} \sec (e+f x) \left (\cos \left (\frac {1}{2} (e+f x)\right )+\sin \left (\frac {1}{2} (e+f x)\right )\right )^3 (c-c \sin (e+f x))^{7/2} \left (-32-\frac {109}{14} \cos (e+f x)+\frac {1}{14} \cos (3 (e+f x))+\frac {64 \sin \left (\frac {1}{2} (e+f x)\right )}{\cos \left (\frac {1}{2} (e+f x)\right )+\sin \left (\frac {1}{2} (e+f x)\right )}+\sin (2 (e+f x))\right )}{f \left (\cos \left (\frac {1}{2} (e+f x)\right )-\sin \left (\frac {1}{2} (e+f x)\right )\right )^7 (a (1+\sin (e+f x)))^{3/2}} \]
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Result contains complex when optimal does not.
Time = 4.26 (sec) , antiderivative size = 1527, normalized size of antiderivative = 5.19
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Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 0.13 (sec) , antiderivative size = 216, normalized size of antiderivative = 0.73 \[ \int \frac {(g \cos (e+f x))^{3/2} (c-c \sin (e+f x))^{7/2}}{(a+a \sin (e+f x))^{3/2}} \, dx=-\frac {2 \, {\left (6 \, c^{3} g \cos \left (f x + e\right )^{2} + 133 \, c^{3} g - {\left (c^{3} g \cos \left (f x + e\right )^{2} - 21 \, c^{3} g\right )} \sin \left (f x + e\right )\right )} \sqrt {g \cos \left (f x + e\right )} \sqrt {a \sin \left (f x + e\right ) + a} \sqrt {-c \sin \left (f x + e\right ) + c} + 231 \, {\left (-i \, \sqrt {2} c^{3} g \sin \left (f x + e\right ) - i \, \sqrt {2} c^{3} g\right )} \sqrt {a c g} {\rm weierstrassZeta}\left (-4, 0, {\rm weierstrassPInverse}\left (-4, 0, \cos \left (f x + e\right ) + i \, \sin \left (f x + e\right )\right )\right ) + 231 \, {\left (i \, \sqrt {2} c^{3} g \sin \left (f x + e\right ) + i \, \sqrt {2} c^{3} g\right )} \sqrt {a c g} {\rm weierstrassZeta}\left (-4, 0, {\rm weierstrassPInverse}\left (-4, 0, \cos \left (f x + e\right ) - i \, \sin \left (f x + e\right )\right )\right )}{7 \, {\left (a^{2} f \sin \left (f x + e\right ) + a^{2} f\right )}} \]
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Timed out. \[ \int \frac {(g \cos (e+f x))^{3/2} (c-c \sin (e+f x))^{7/2}}{(a+a \sin (e+f x))^{3/2}} \, dx=\text {Timed out} \]
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\[ \int \frac {(g \cos (e+f x))^{3/2} (c-c \sin (e+f x))^{7/2}}{(a+a \sin (e+f x))^{3/2}} \, dx=\int { \frac {\left (g \cos \left (f x + e\right )\right )^{\frac {3}{2}} {\left (-c \sin \left (f x + e\right ) + c\right )}^{\frac {7}{2}}}{{\left (a \sin \left (f x + e\right ) + a\right )}^{\frac {3}{2}}} \,d x } \]
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Timed out. \[ \int \frac {(g \cos (e+f x))^{3/2} (c-c \sin (e+f x))^{7/2}}{(a+a \sin (e+f x))^{3/2}} \, dx=\text {Timed out} \]
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Timed out. \[ \int \frac {(g \cos (e+f x))^{3/2} (c-c \sin (e+f x))^{7/2}}{(a+a \sin (e+f x))^{3/2}} \, dx=\int \frac {{\left (g\,\cos \left (e+f\,x\right )\right )}^{3/2}\,{\left (c-c\,\sin \left (e+f\,x\right )\right )}^{7/2}}{{\left (a+a\,\sin \left (e+f\,x\right )\right )}^{3/2}} \,d x \]
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